110
 2;; 10
 3
 4(+ 5 3 4)
 5;; 12
 6
 7(- 9 1)
 8;; 8
 9
10(/ 6 2)
11;; 3
12
13(+ (* 2 4) (- 4 6))
14;; 6
15
16(define a 3)
17a 
18;; 3
19
20(define b (+ a 1))
21b 
22;; 4
23
24(+ a b (* a b))
25;; 19
26
27(= a b)
28;; #f
29
30(if (and (> b a) (< b (* a b)))
31    b
32    a)
33;; returns value of b
34;; 4
35
36(cond ((= a 4) 6)
37      ((= b 4) (+ 6 7 a))
38      (else 25))
39;; returns 16 because:
40;; a = 3
41;; b = 4
42;; if b equals 4, return 6 + 7 + a
43;; 6 + 7 + 3 = 16
44
45(+ 2 (if (> b a) b a))
46;; this one confused me
47;; because it sounds like it should be:
48;; if b is greater than a, return (b a)
49;; since b (4) is greater than a (3), return 4 3
50;; then sum 2 4 3 = 9
51;; but when I run:
52(if (> b a) b a)
53;; I get:
544
55;; what I realized I was forgetting is that
56;; the if statement is saying:
57;; if b is greater than a, return b, else return a
58;; since b (4) is greater than a (3), return 4
59;; then sum 2 4 = 6
60
61(* (cond ((> a b) a)
62         ((< a b) b)
63         (else -1))
64   (+ a 1))
65;; if a is greater than b, return a
66;; else if a is less than b, return b
67;; else return -1
68;; then add 1 to a and multiply by the result of the
69;; first conditional
70
71;; so in this case:
72;; a is less than b, so return b which is 4
73;; since (+ a 1) is 3 + 1 is 4
74;; 4 * 4 = 16